Remove log when no handshake message is sent (#452)

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John Maguire 2021-04-30 19:19:40 -04:00 committed by GitHub
parent 1bc6f5fe6c
commit 98c391396c
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2 changed files with 9 additions and 6 deletions

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@ -41,7 +41,7 @@ jobs:
run: make test run: make test
- name: End 2 end - name: End 2 end
run: make e2e run: make e2evv
test: test:
name: Build and test on ${{ matrix.os }} name: Build and test on ${{ matrix.os }}
@ -77,4 +77,4 @@ jobs:
run: go test -v ./... run: go test -v ./...
- name: End 2 end - name: End 2 end
run: go test -tags=e2e_testing -count=1 ./e2e run: make e2evv

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@ -165,10 +165,13 @@ func (c *HandshakeManager) handleOutbound(vpnIP uint32, f EncWriter, lighthouseT
} }
}) })
hostinfo.logger(c.l).WithField("udpAddrs", sentTo). // Don't be too noisy or confusing if we fail to send a handshake - if we don't get through we'll eventually log a timeout
WithField("initiatorIndex", hostinfo.localIndexId). if len(sentTo) > 0 {
WithField("handshake", m{"stage": 1, "style": "ix_psk0"}). hostinfo.logger(c.l).WithField("udpAddrs", sentTo).
Info("Handshake message sent") WithField("initiatorIndex", hostinfo.localIndexId).
WithField("handshake", m{"stage": 1, "style": "ix_psk0"}).
Info("Handshake message sent")
}
// Increment the counter to increase our delay, linear backoff // Increment the counter to increase our delay, linear backoff
hostinfo.HandshakeCounter++ hostinfo.HandshakeCounter++